Calculate the mass of oxygen in 65.2g of the compound c3h8o3

Answer 1

Molar mass (MM) of Oxygen: 16.00 g / mol

MM of C₃H₈O₃: 92.09 g / mol

(65.2 g C₃H₈O₃) x (1 mol C₃H₈O₃ / 92.09 g C₃H₈O₃) x (3 mol O / 1 mol C₃H₈O₃) x (16.00 g O / 1 mol O) = 33.98 g O

Thus, 33.98 g of Oxygen are present.

Answer 2

In C₃H₈O₃92 grams of compound so we sewt , there are 3 moles of oxygen atoms per molecule or 48 grams/92 grams of compound, so we set up a proportion, 48/92=X/65.2 where X= grams of oxygen. Solve for X, 34.01 grams oxygen. You could also state oxygen is 48/92 or 52.17% and multiply (65.2)(0.5217)=34.01grams