What mass of potassium hydroxide would be required to produce 9.38g of the antacid milk of magnesia by the reaction of MgCl2 with KOH?

Answer 1

Write the balanced chemical reaction. Milk of magnesia is magnesium hydroxide, which has the chemical formula Mg(OH)₂.

MgCl₂ + 2 KOH → Mg(OH)₂ + 2 KCl

Stoichiometric conversion is as follows:

g Mg(OH)₂ → mol Mg(OH)₂ → mol KOH → g KOH

9.38 g Mg(OH)₂ x (1 mol Mg(OH)₂ / 58 g Mg(OH)₂) x (2 mol KOH / 1 mol Mg(OH)₂) x (56 g KOH / 1 mol KOH) = 18.1 g KOH