Cannot figure how to output numbers horizontally in Java

Question

This is my code, it is suppose to output 10 numbers per line but it only works with the #7. I am ask to make the code user input-able, which that part is done.

import java.util.Scanner;

public class CountByAnything

{

// Modify the code below

public static void main (String args[])

{

Scanner input = new Scanner(System.in);

System.out.println("Enter a value");

int alpha = input.nextInt();

int START = alpha;

final int STOP = 500;

final int NUMBER_PER_LINE = 10;

for(START = alpha; START <= STOP; START += alpha)

{

System.out.print(START + " ");

if(START % NUMBER_PER_LINE == alpha)

System.out.println();

}

}

}

Answer 1

Okay so from the code you have posted there I'm assuming you want to print 10 numbers that increment by the original number? For example.

User input of 5 would print

5 10 15 20 25 30 35 40 45 50

If so the following code will do that

Scanner input = new Scanner(System.in);

System.out.println("Enter a value");

int alpha = input.nextInt();

int START = alpha;

final int STOP = 500; //i dont think you need this anymore

final int NUMBER_PER_LINE = 10;

//we only run our for loop for the number of 'numbers' we want to print. 0 to 9 is 10 values

for(int i = 0; i < NUMBER_PER_LINE; i++)

{

System.out.print(START + " ");

START = START + alpha; //increase current number by user input value

//when we get to the last number that we want to print, print a new line

if(i == NUMBER_PER_LINE - 1){

System.out.println();

}