
Mark M. answered 01/08/15
Tutor
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Mathematics Teacher - NCLB Highly Qualified
Absolute equations must be solved twice. Once assuming the argument (the stuff inside the | | is positive, and once assuming it is negative.
If x - 1 is positive
|x - 1| = 5x + 10
x - 1 = 5x + 10
-1 = 4x + 10
-11 = 4x
-11/4 = x
If x - 1 is negative
|x - 1| = 5x + 10
-(x - 1) = 5x + 10
-x + 1 = 5x + 10
1 = 6x + 10
-9 = 6x
-9/6 = x
-3/2 = x
The second question is done the same way.