
Mary Ann F. answered 12/28/14
Tutor
5.0
(1,040)
Math & Science... Algebra and Geometry specialist
It will really help you to draw a diagram and label all the parts.
_______________________
| } x the width of the mat is x and is the same in the
|_x____________________ horizontal and vertical dimensions.
| | |
| | 5cm |
| x |________________ |
| }x 10 cm
|______________________
Let's figure the area of the mat:
it's 2x + 10 in the horizontal dimension and
2x + 5 in the vertical dimension.
To find the area we need to multiply these dimensions together and then subtract out the area of the picture in the middle. The problem tells us that this area is twice the picture so we can set it equal to 100.
(2x +10)(2x +5) - 50 = 100
(4x2 + 30x + 50) - 50 = 100
4x2 +30x -100 = 0
factor out a 2
2(2x2 + 15x - 50) = 0
2(2x - 5)(x + 10) = 0
used zero product property, and realize that the dimension must be positive, so we can discard the negative answer ( x+10 = 0, x = -10)
2x - 5 = 0
x = 5/2 or x = 2.5 cm
you can check your answer...... plug it back in. Let me know if this helps.