How come an array's address is equal to its value in C?

Question

In the following bit of code, pointer values and pointer addresses differ as expected.But array values and addresses don't!How can this be?Output my_array = 0022FF00 &my_array = 0022FF00 pointer_to_array = 0022FF00 &pointer_to_array = 0022FEFC<!--formatting fix --> #include <stdio.h> int main() { char my_array[100] = "some cool string"; printf("my_array = %p\\n", my_array); printf("&my_array = %p\\n", &my_array); char *pointer_to_array = my_array; printf("pointer_to_array = %p\\n", pointer_to_array); printf("&pointer_to_array = %p\\n", &pointer_to_array); printf("Press ENTER to continue...\\n"); getchar(); return 0; }

Answer 1

The name of an array is always equal to the address of its zeroth element. So

int table[20];

table is same as &table[0] and it is same as table + 0

similarly, table + 4 is same as &table[4]