How do you format an unsigned long long int using printf?

Question

#include <stdio.h> int main() {  unsigned long long int num = 285212672; //FYI: fits in 29 bits  int normalInt = 5;  printf("My number is %d bytes wide and its value is %ul. A normal number is %d.\\n", sizeof(num), num, normalInt);  return 0; }Output: My number is 8 bytes wide and its value is 285212672l. A normal number is 0.I assume this unexpected result is from printing the `unsigned long long int`. How do you `printf()` an `unsigned long long int`?

Answer 1

Use the flag %llu instead of %ul in the printf, for the number's value:

#include <stdio.h>

int main(){

unsigned long long thingull = 3022123456789101167;

printf ("%llu\n", thingull);

}