How to find the 'sizeof' (a pointer pointing to an array)?

Question

First off, here is some code: int main() { int days[] = {1,2,3,4,5}; int *ptr = days; printf("%u\\n", sizeof(days)); printf("%u\\n", sizeof(ptr)); return 0; }Is there a way to find out the size of the array that `ptr` is pointing to (instead of just giving its size, which is four bytes on a 32-bit system)?

Answer 1

#include <stdio.h>

int main()

{

int days[] = {1,2,3,4,5};

int *ptr = days;

printf("%u\\n", sizeof(days)/4);

// printf("%u\\n", sizeof(ptr));

return 0;

}