Why does sizeof(x++) not increment x?

Question

Here is the code compiled in dev c++ windows: #include int main() { int x = 5; printf("%d and ", sizeof(x++)); // note 1 printf("%d\\n", x); // note 2 return 0; }I expect `x` to be 6 after executing **note 1**. However, the output is: 4 and 5Can anyone explain why `x` does not increment after **note 1**?

Answer 1

The size of an object is more than likely computed at compile time. Its not computed dynamically at run time. That would explain the fact that value of the object does not get altered after doing the "sizeof" operator on the object.