Trenda M.

asked • 11/03/14

Photoelectron Spectroscopy

I'm really stuck on this one.  I do not know where to begin and I am struggling with chemistry so if you could get me on track or help me figure out how solve this problem I would be very grateful.
One way to measure the ionization energy of atoms is to shine light with a specific wavelength at gas phase atoms, causing the outermost electrons to be ejected.  The kinetic energy (T) of these electrons can be found by measuring the velocity of the ejected electrons.  If Ep is the energy of the incident light, then by the conservation of energy Ep = Ei1 + T.  What is the ionization energy of rubidium (in kJ mol-1) if an incident light of 58.4 nm produces electrons with a velocity of 2.450x10^6 ms-1?

1 Expert Answer


Trenda M.

What does the 58.4 nm refer to? Wavelength? 


Francisco P.

Yes.  Don't forget to convert nanometer (nm) to meter.


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