Trenda M.

asked • 11/03/14

Photoelectron Spectroscopy

I'm really stuck on this one.  I do not know where to begin and I am struggling with chemistry so if you could get me on track or help me figure out how solve this problem I would be very grateful.
 
One way to measure the ionization energy of atoms is to shine light with a specific wavelength at gas phase atoms, causing the outermost electrons to be ejected.  The kinetic energy (T) of these electrons can be found by measuring the velocity of the ejected electrons.  If Ep is the energy of the incident light, then by the conservation of energy Ep = Ei1 + T.  What is the ionization energy of rubidium (in kJ mol-1) if an incident light of 58.4 nm produces electrons with a velocity of 2.450x10^6 ms-1?

1 Expert Answer

By:

Trenda M.

What does the 58.4 nm refer to? Wavelength? 
Report

11/03/14

Francisco P.

tutor
Yes.  Don't forget to convert nanometer (nm) to meter.
Report

11/03/14

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.