SURENDRA K. answered • 10/05/14

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Let us formulate the equations for the given data---

Say, we have x nos of packs of economy blend

y nos of packs of superior blend.

3x+11y <=1584

6x+4y <=1440

Making a graph of these two equations,we get the following three extreme points----

(240,0) , (0,144) , (176,96)

The objective function is

Max (2x +4y)

Let us now calculate value of objective function at these extreme points

For (240,0). Value of objective function =2*240=480

For (0,144) value of objective function=4*144=576

For (176,96) value of objective function =2*176+4*96=736

So (176,96). Is the optimal point

That means x=176

y=96

This is basically a linear programming problem.