SURENDRA K. answered 10/05/14
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Let us formulate the equations for the given data---
Say, we have x nos of packs of economy blend
y nos of packs of superior blend.
3x+11y <=1584
6x+4y <=1440
Making a graph of these two equations,we get the following three extreme points----
(240,0) , (0,144) , (176,96)
The objective function is
Max (2x +4y)
Let us now calculate value of objective function at these extreme points
For (240,0). Value of objective function =2*240=480
For (0,144) value of objective function=4*144=576
For (176,96) value of objective function =2*176+4*96=736
So (176,96). Is the optimal point
That means x=176
y=96
This is basically a linear programming problem.