We are looking for an integer n such that
f(n/2)<0
and
f((n+1)/2)>0.
The function f is always increasing, so we expect to have one zero.
Let n =0.
Then,
f(0) = 03 + 2•0 + 4=4>0
This means n should be negative.
Let try n=-1.
f(-1/2)=(-1/2)3 + 2•(-1/2)+4
=-1/8-1+4=2 7/8.
This means -1 could be our RIGHT endpoint if f(-1) is negative. If it is positive, we check the next value for n.
Can you finish the problem now?