solve the question complete

Question

a+2∕a²-4 ÷ a+3∕a-2

Answer 1

You are missing some parentheses, , but I think the expression is:

 

(a+2)/(a²-4) ÷ (a+3)/(a-2)

 

When you divide by a fraction, the rule is to invert the fraction (change to its reciprocal) and multiply:

 

= (a+2)/(a²-4) × (a-2)/(a+3)

 

You should recognize that a²-4 is a difference of squares, so a²-4 = (a+2)(a-2):

 

= (a+2)/(a+2)(a-2) × (a-2)/(a+3)

 

Can you finish it from here?

Answer 2

It's very probable that you intended to have a rational algebraic expression here. Therefore parentheses are REQUIRED to enclose any multi-term numerator and any multi-term denominator.

 

The appropriate technique is to factor the denominators, and to obtain a common denominator for the two rationals.

 

You should do the work, after noting the necessity of proper parenthesization.