The derivative to find the equation line tangent to the curve

Alexandr K. answered • 02/02/18

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The life of a Math teacher is to give you problems.

Try using the power rule. Remember that the derivative of a sum is the same as the sum of the derivatives. Give it a shot and come back with a question if you're still confused.

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The derivative to find the equation line tangent to the curve

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f'(x) = 2(2/3)x-1/3 - (5/3)x2/3 = (4/3)x-1/3 - (5/3)x2/3 f"(x) = (4/3)(-1/3)x-4/3 - (5/3)(2/3)x-1/3 = (-4/9)x-4

f(x)=x^2/3 * (2-x) = x^2/3 * (2-x)

inverse derivative: y=sec^-1 1/t

Urgent! Please help me! I have an exam in two days and I really need help with these questions. Please explain the steps and answers as thoroughly as possible.

derivatives

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The derivative to find the equation line tangent to the curve

1 Expert Answer

Still looking for help? Get the right answer, fast.

OR

RELATED TOPICS

RELATED QUESTIONS

f'(x) = 2(2/3)x-1/3 - (5/3)x2/3 = (4/3)x-1/3 - (5/3)x2/3 f"(x) = (4/3)(-1/3)x-4/3 - (5/3)(2/3)x-1/3 = (-4/9)x-4

f(x)=x^2/3 * (2-x) = x^2/3 * (2-x)

inverse derivative: y=sec^-1 1/t

Urgent! Please help me! I have an exam in two days and I really need help with these questions. Please explain the steps and answers as thoroughly as possible.

derivatives

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