
Dattaprabhakar G. answered 07/28/14
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f (f (x)) = sqrt (f(x)) - 1 = sqrt (sqrt(x) - 1) - 1.
g( f(x) ) = 1 / [sqrtx-1]. Assuming that f(x) is real-valued, x must be non-negative; so x >= 0.
We can not have 0 in the denominator of g(f(x)). Hence the domain of g(x) is 0 =< x < 1 and 1 < x =< +infinity.