
Kenneth S. answered 09/08/17
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
The data supplied, for a family of five dogs, is erroneous because it declares that the two grown dogs have ages thirty-four each. Definitely not believable. Nevertheless...
This implies that, from least to greatest, the P1 P2 P3 A1 A2 (puppy ages & adult dog ages) must be 1, 2, 7, 34, 34 so that average (mean) is 16; (1+P2+7+34+34)/5 = 16.
Thus 80 = (1+P2+7+34+34)
80 - P2 +76
P2 = 4
The age of the middle dog is 4. Those adult dogs may have set a record, though!