F(x)=x^3-3x+28

Question

How to solve using listing rational zeros by steps. Having trouble with these?

Answer 1

Are you sure this equation is correct?  The only possible rational zeros are + or - {1, 2, 4, 7, 14, 28} and I don't think any of these work.  The only way I see to solve this is graphing.  If the equation is:

 

F(x) = x² - 3x - 28, try factoring, using x - 7, and x + 4 as factors.

 

Kevin