Write the equation of a line parallel to the given line but passing through the given point.

Question

y=-3x-6;(-1, 5)     

Answer 1

Write the equation of a line parallel to the given line but passing through the given point.
y=-3x-6; (-1, 5)

 

The slope intercept form of a straight line is:

 

y = mx + b

 

Where m = the slope and b is the y-intercept (the point where the line crosses the y-axis). Two lines are parallel if they have the same slope, m.

 

In your problem, the first line is y = (-3)x -6.  The second line, which I'll call y₂ must also have a slope of -3:

 

y₂ = (-3)x + b

 

To find b, plug in the values of the given point on the line (-1,5) for x and y:

 

y₂ = (-3)x + b

 

5 = (-3)(-1) + b

 

Solve for b then add its value in to the y₂ equation above.

 

 

Answer 2

You can also use the point-slope form.

Parallel lines have the same slope.

y-y₁=-3(x-x₁)

y-5=-3(x-[-1])

y-5=-3x-3

y=-3x-3+5

y=-3x+2