
Steve S. answered 03/21/14
Tutor
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(3)
Tutoring in Precalculus, Trig, and Differential Calculus
Find the fourth roots of 625 i.
z = 625 i = 625 e^(i (pi/2 + 2n pi)), n integer.
z^(1/4) = 5 e^(i (pi/8 + n pi/2)), n integer.
n = 0, z^(1/4) = 5 e^(i (pi/8 ))
n = 1, z^(1/4) = 5 e^(i (pi/8 + pi/2)) = 5 e^(i 5pi/8)
n = 2, z^(1/4) = 5 e^(i (pi/8 + pi)) = 5 e^(i 9pi/8)
n = 3, z^(1/4) = 5 e^(i (pi/8 + 3 pi/2))= 5 e^(i 13pi/8)
n = 4, z^(1/4) = 5 e^(i (pi/8 + 2 pi)) = 5 e^(i (pi/8 ))
So there are 4 distinct fourth roots for n = 0,1,2,3.
They are equally spaced around a circle centered at the origin of the Argand Plane with radius 5.
Daisy R.
Thank you for the help :)
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03/21/14
Daisy R.
03/21/14