What is the characteristic wavelength of this electron? (Mass of electron is 9.1094*10^-31 kg)

Question

The electron microscope has been widely used to obtain highly magnified images of biological and other types of materials. When an electron is accelerated through a particular potential field, it attains a speed of 9.82*10^6 m/s. 

Answer 1

v= fλ

E = hf = ½mv² 

 

λ = h/mv = (6.63x10^-34)/ [(9.1094x10^-31)(9.82x10⁶)]

 

I hope this helps!