Roman C. answered 02/06/17
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limn→∞ ∑i=0n-1 1/√(4n2-i2) = limn→∞ (1/n)∑i=0n-1 1/√(4-(i/n)2) = ∫01 1/√(4-x2) dx.
Note that ∫01 1/√(4-x2) dx = sin-1(x/2)|01 = sin-1(1/2) = π/3.