Odds of getting at least 16 of 24 trials correct, each trial with probability of .25 for each.

Question

I am trying to find out what the odds are of getting at least 16 out of 24 trials correct where the probability of getting any one trial correct is .25 or 25%. My calculations give me a Cumulative Probability: P(X > or = 16) is 2.02210569919536E-05 or a probability of .0000202210569919536. Does that mean that the odds of getting at least 16 out of 24 correct with a probability of 25% on each trial would be equal to about 1 in 50,000?

Answer 1

Just to confirm, I also got the same odds as you, 2.022 * 10^-5.

 

Your analysis is correct.  The odds would be about 1:49453 that you would get at least 16 successes out of 24 trials.