which function has a vertex in quadrant 2?

Question

A. f(x)=2(x+2)(x-1) B.f(x)=(x-1)2 -2 C.f(x)= (x-1)(x+3) D. f(x)=-(x+3)2 E. f(x)=-2x2-8x+3 F. f(x)=1/2x2-2

Answer 1

From the vertex form, of which you should know by now, the vertex (h, k) is in the 2nd quadrant when

 

h < 0

k > 0

 

Find the function that satisfies this condition.