which functions have a vertex that is a maximum point? A. f(x)=2(x+2)(x-1) B.f(x)=(x-1)2 -2 C.f(x)= (x-1)(x+3) D. f(x)=-(x+3)2 E. f(x)=-2x2-8x+3 F. f(x)=1/2x2-2

Question

A. f(x)=2(x+2)(x-1) B.f(x)=(x-1)2 -2 C.f(x)= (x-1)(x+3) D. f(x)=-(x+3)2 E. f(x)=-2x2-8x+3 F. f(x)=1/2x2-2

Answer 1

The leading term must be a negative coefficient.  Which one of these functions will have a leading term, when expanded, will have a leading term with a negative coefficient?

 

Choice D is one function.  There is another.  Can you find it?