If you wanted the probability that they both die on a particular same day of the year (say January 12th), then the answer would be (1/365)2, as Jason said. However, the requirement is simply that the both die on the same day, not necessarily on a particular day. Therefore, given that person A dies on a day, there is (1/365) chance that person B dies on the same day.
If that doesn't make sense, we can also take a combinatorics approach. If each event is equally likely, then probability equals the number of combinations that meet the criteria divided by the total number of possible combinations. Each person is equally likely to die on any day of the year (ignoring winter roads, 4th of July parties, etc. that actually modify probabilities), so there are 3652 combinations of how the two people could die. There are however 365 combinations that meet the criteria of both people dying on the same day (i.e. one combination for each day of the year). Therefore, the probability is
# that meet criteria / # total = 365 / 3652 = 1 / 365
If that still doesn't make sense or if you have any further questions on probability or combinatorics, please let me know.
Shawn M.
So my question is what is the probability of my father and his siblings. They all three died on February 3rd. Exactly 14 years apart from each other's deaths . What is the probability?02/22/23