Descartes rule of signs

Question

By Descarte's rule of signs 

P(x)=x³-2x²-3x-3

has how many positive real zeros ?

has how many negative real zeros (enter the smaller number first)

Answer 1

P(x) = x^3 - 2x^2 - 3x - 3

              +1        +0   +0    = 1 positive real zero

 

P(-x) = -x^3 - 2x^2 + 3x - 3

                           +1     +1  = 0 or 2 negative real zeros and 2 or 0 complex zeros