
Norbert W. answered 07/26/16
Tutor
4.4
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Math and Computer Language Tutor
r1 = <3 + 2t, 3t, -4t> = <3, 0, 0> + t<2, 3, -4>, v1 = 2i + 3j - 4kr2 = <t, t, -t> = <0, 0, 0> + t<1, 1, -1>, v2 = i + j - k
Let v be a vector perpendicular to both vectors v1 and v2.
This can be done by v = v1 x v2
v = |i j k| This is a determinant.
|2 3 -4|
|1 1 -1|
= (-3+ 4)i (-4+2)j + (2-3)k
= i -2j - k
Then the vector perpendicular to r1 and r2 going through the
point (1, 0, -1) is r3 = <1, 0, -1> + t<1, -2, -1>
= <1+t, -2t, -1-t>