Assuming that the function is f(x) = (4x-2)/(x+7),
f'(x) = [4(x+7)-(4x-2)]/(x+7)2 = 30/(x+7)2>0 for all x ≠ -7
So, f is increasing on (-∞,-7)∪(-7,∞). There are no intervals on which f is decreasing since f'(x) is never negative.
f"(x) = -60(x+7)-3 = -60/(x+7)3
f"(x) > 0 when x < -7 and f"(x) < 0 when x > -7
f is concave up on (-∞,-7) and is concave down on (-7,∞).
Ana B.
06/22/16