write an equation of the line that passes through point p and is perpendicular to the line with the given equation. P(2,4);y=-8x-3

Question

please help

Answer 1

First, find the slope of the original equation.  In this case, the slope is -8.  You know that perpendicular lines have slopes that are negative reciprocals, so the negative reciprocal of -8 is 1/8.  You new line will have a slope of ?.

 

Now, use this new slope and the given point to find the y-intercept:

 

y = mx + b

4 = (?)(2) + b

4 = ? + b

15/4 = b

 

Use the new slope and y-intercept to write the new linear equation:

 

y = 1/8x + 15/4