
Steve S. answered 12/09/13
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
(5x^2+20)(3x^2-48)=0
Use zero-product rule:
Case 1: 5x^2+20 = 0; 5x^2 = -20; x^2 = -4; |x| = 2*sqrt(-1); x = +-2i
Case 2: 3x^2-48 = 0; 3x^2 = 48; x^2 = 16; |x| = 4; x = +-4
Real Roots are x = +-4 and the Imaginary Roots are x = +-2i.