
Andrew M. answered 05/02/16
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
year 1: $47,000
year2: 1.04(47000) = $48,880
year 3: 1.04(48,880) = $50,835.20
year 4: 1.04(50,835.20) = $52,868.61
year 5: 1.04(52,868.61) = $54,983.35
total: $254,567.16

Andrew M.
5
∑(Tn + 1.4Tn-1)
n=1
given T1= $47,000
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05/02/16

Andrew M.
That's not quite right.
For the total Tn each year
Tn = Tn-1 + 1.4Tn-1
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05/02/16
Jackson L.
For the summation method what would be the expression to be used after the summation sign, specifically related to this figure of $47000? Hey Andrew, thank you so much for what you have sent me.
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05/02/16
Jackson L.
05/02/16