Roman C. answered 04/25/16
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Masters of Education Graduate with Mathematics Expertise
y=4
(0,4) --------------- (2,4)
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x=0 | / y=x2
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(0,0)
We have to integrate out x first, since the indefinite integral ∫ exp(y2) dy has no closed form.
Therefore we must use horizontal slices. At level any level 0 ≤ y ≤ 4, we have 0 ≤ x ≤ √y
Thus the iterated integral is:
∫04 ∫0√y x exp(y2) dx dy
= ∫04 x2 exp(y2)/2 |0√y dy
= (1/4) ∫04 2y exp(y2) dy
= (1/4) ∫016 eu du ← u-substitution: u=y2, du = 2y dy
= eu/4 |016 = (e16 - 1)/4