Matthew M. answered 01/12/16
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PhD Student in Chemistry with 6+ Years of Teaching Experience
A) Al2(SO4)3 x 18H2O
To determine this, you only need to pay attention to the charge of the common ion (SO4).
Since SO4 is typically -2, we can assume that there are six negative charges in this complex. Since there are two Al atoms, each has an oxidation state of +3.
In this particular complex, we can ignore the water molecules since they are not included in brackets, thus not coordinated to the metal atom.
B) (Al(H2O)6)3+)
In this complex, the six water molecules represent 3 negative charges (half the number of water molecules). So, if the overall complex is +3 (indicated by the superscript after the complex), then the Al atom must be in the +6 oxidation state.
C) (Ag(NH3)2)+
For this complex, we treat ammine (NH3) ligands as neutral ligands. So, if the overall charge of the complex is +1, then the Ag atom must be in the +1 oxidation state.
Hope this helps! Feel free to contact me with any inorganic questions in the future!