Data for the given equation is...
y=(-1/3)x-6
m1= -1/3
y-intercept is (0,-6)
m2=3.....slope of a perpendicular line to the given (negative
reciprocal of "m1")
For P=(4,5), substitute these values into the point-slope
form equation "y=mx2+b" where "m2=3".
5=3(4)+b....solve for "b"
m1= -1/3
y-intercept is (0,-6)
m2=3.....slope of a perpendicular line to the given (negative
reciprocal of "m1")
For P=(4,5), substitute these values into the point-slope
form equation "y=mx2+b" where "m2=3".
5=3(4)+b....solve for "b"
b=7
...and rewrite new perpendicular point-slope equation...
y=3x-7........new perpendicular line passing thru P(4,5)
Substitute point P(4,5) into this new equation to check
for truth...
5=3(4)-7
5=12-7
5=5.........true, √check, new perpendicular line equation
is correct.
Always check your solution and work.