Roman C. answered 12/13/15
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Masters of Education Graduate with Mathematics Expertise
∫(4+eyz) dx = 4x + xeyz + f(y,z)
∫(xzeyz + 2yz) dy = xeyz + y2z + g(x,z)
∫(6z2 + xyeyz + y2) dz = 2z3 + xeyz + y2z + h(x,y)
This is a conservative field since we can take
f(y,z) = y2z + 2z3
g(x,z) = 4x + 2z3
h(x,y) = 4x
Thus F(x,y,z) = ∇U(x,y,z) where
U(x,y,z) = 4x + y2z + 2z3 + xeyz
Thus by the Fundamental theorem of line integrals, the answer is
U(2,-1,7) - U(1,2,3)
= (4·2 + (-1)2·7 + 2·73 + 2e(-1)·2) - (4·1 + 22·3 + 2·33 + 1·e2·3 )
= (687 + 2e-2) - (70 + e6)
= 617 - e6 + 2/e2