
Steven G. answered 09/19/15
Tutor
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(1)
Semi-retired with loads of real-life math experience.
a = (-4, 2, 4) and b = (1, 0, -1)
a•a = (-4)(-4) + (2)(2) + (4)(4) = 36
a•b = (-4)(1) + (2)(0) + (4)(-1) =-8
b•b = (1)(1) + (0)(0) + (-1)(-1) =2
|a| = 6
|b| = √2
There exists a scalar, σ, and a vector u such that
- u is perpendicular to a
- b = σa + u
- σ|a| is the scalar projection of b onto a
- σa is the vector projection of b onto a
Then a•b = σ a•a + a•u ⇒
a•b = σ a•a ⇒
σ = a•b / a•a = -8/36 = -2/9
The scalar projection of b onto a is σ|a| = (-2/9)(6) = -4/3
The vector projection of b onto a is σa = (-2/9)(-4, 2, 4) = (8/9, -4/9, -8/9)