a 6% chlorine solution is mixed with an 18% chlorine solution to create 8 liters of a 15% chlorine solution. how much of each strength of chlorine was mixed?

Question

show me how to solve

Answer 1

The trick to this mixture problem is to calculate the amount of chlorine in each component and in the final mixture. Then you can write the second equation that you need.

 

A = amount of 6% solution

B = amount of 18% solution

 

Total of A and B is 8 liters

A + B = 8

 

Chlorine in A + Chlorine in B = Chlorine in final mixture.

0.06A + 0.18B = 0.15 * 8

 

A + B = 8

0.06A + 0.18B = 1.2

 

0.06A + 0.06B = 0.48   -- (= 0.06 * 8)

 

             0.12B = 0.72

 

B = 6 liters of 18%

A + 6 = 8

A = 2 liters of 6%