02/16/21

Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x
Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x
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02/16/21

How can I use definite integrals to solve the given problem?

A particle P moves in a straight line so that at t seconds, its displacement, s meters from the starting point is s=t^3-7t^2+17t. Determine the interval of time when the particle is moving at an... more
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02/15/21

A conical tank has height 10 ft and radius 8 ft. The tank is buried vertex-down so that the top is 6 ft underground. The tank is filled with kerosene (of density 51.2lb/ft^3).
a) Calculate the total fluid force on the side of the tank.b) Calculate the work required to pump the oil to ground level.
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02/15/21

Calculus graphing problem
Sketch two periods of the graph of the function: h(x)=5sec((Pi/4)(x+1)) Identify the stretching factor, period, and asymptotes.
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02/09/21

Please Help - Basic Calculus Word Problem...
A bazaar is supplied n thousands of crates of apples daily when it is sold at x pesos per crate and the supply equation isxn - 3x -100x -100 = 0,If the supply daily is decreasing by 250 crates a... more
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02/08/21

Transformations
if the range of y = f(x) is -1 ≤ y ≤ , determine the range of y= -3 f (1/2x)+4
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02/04/21

Consider f ' (x) = 6x^2 + 2 and (-1,2) lies on the graph of f. Find the equation for f(x).
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02/01/21

Find all values of 𝑐 such that 𝑓(𝑥)=𝑥+9/𝑥^2+2𝑐𝑥+4 has domain 𝑅. (Express numbers in exact form. Use symbolic notation and fractions where needed. Give the inequality in terms of 𝑐.
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08/27/20

For the following exercise, find the domain of the function using interval notation. f ( x ) = 3 √ 4 − 5 x
For the following exercise, find the domain of the function using interval notation. f ( x ) = 3 √ 4 − 5 x
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07/20/20

Find the equation of the tangents and normal line at the points indicated y=x^3-7x^2+15x-9 at its points of intersection with the x-axis
Please help me with this. Thank you.
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04/23/20

Solve tan(x) + 3 cot(x) - 5 sec(x) = 0 where 0<x<180°
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