08/13/21
Regression Equations
The income of a small business for several years is given in the table below.Year/Thousands of Dollars1960/13.81961/58.61962/66.81963/61.81964/41.11965/28.81966/351967/67.4a) Perform regression to...
more
08/11/21
CHEMISTRY QUESTION ON RATE OF CHEMICAL REACTION
QUESTION22.1. List four factors that can increase the rate of a chemical reaction. 2.2 What two factors determine whether a collision between molecules will lead to a chemical reaction? 2.3...
more
01/27/21
Particle Motion (Again)
A particle moves along a straight line with velocity given by v(t) = 5-(1.03)^t^2 at time t ≥ 0. What is the acceleration of the particle at time t = 6?
01/27/21
Converting compound from mass (g) to # of atoms
Convert 0.20 grams of CaCO3 to number of atoms.: (molar mass is 100.09 g CaCO3)Which is correct? # 1 or # 2?Method # 10.20 g CaCO3 x 1 mol CaCO3 / 100.09 g CaCO3 x6.02 x 10^23 molecules CaCO3 / 1...
more
01/27/21
Solving linear systems using technology
The senior classes at high school A and high school B planned separate trips to the state fair. The senior class at high school A rented and filled 2 vans and 8 busses with 360 students. High...
more
01/27/21
Solving linear systems using technology
The senior classes at high school A and high school B planned separate trips to the state fair. The senior class at high school A rented and filled 2 vans and 8 busses with 360 students. High...
more
01/27/21
The reaction N2 (g)+ 3H2 (g)→ 2NH3 (g) is used to produce ammonia (NH3) commercially. If 1.4 g of N2 is used in the reaction, how many grams of H2 will be needed?
I need help in chemistry very much!
01/27/21
Carry out the following calculation, making sure that your answer has the correct number of significant figures:
7.80 g divided by 15.9 g minus 8.37 g
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.