10/03/13

When does 2nd car catch 1st car?

1st Car leaves point A at 5pm at avg speed of 80km/hr. Second car leaves point A 45 minutes later at 110km/hr. When does the 2nd car catch the 1st car. Show working.

10/03/13

Rewrite formulas and equations.

1. Solve for t in the equation -9 = t + 4s 2. Solve for A: B = 5/7(A - 11)

Solve the given linear system.

Solve the given linear system.   a. y = 5x - 3    y = 3x - 1     b. -2x + 3y = 8     3x + 5y = -12   c. 2x - 4y = -6   -x + 2y = 3   d. 5x + 10y = 70    5x + 25z = 270    10y + 25z =... more

10/02/13

find the domain and range

suppose that f(x) = √(x2 -72)  and g(x)= √(7-x)   for each function (h) below, find a formula for h (x) and the domain of h ( use internal notation) a) h(x) = f composed with g of (x) b) h(x) =... more

09/02/13

if there are two events, what probability expression best describes an exactly one suitation

using the union, intersection and complement expressions

06/11/13

x-2y=10 1/2x-2y=4

x-2y=10 1/2x-2y=4 please help and show step by step instructions

06/11/13

x=y-8 -x-y=0

x=y-8 -x-y=0 please help and show step by step

Quadratic Equation Help

I'm solving a quadratic equation which is 2x^2-x-10=0 and I know that a=2 b=-1 and c=-10 ans with the problem put it into the formula which is -(-10 +- √ -1^2-4(2)(-10) and when I get my answer I... more

02/19/13

Define when two events are mutually exclusive by an equation.

Define when two events are mutually exclusive by an equation.

11/01/12

how is the derivative of the inverse tan function = 1/sec2(tan^-1)

how do i get to that point how is it proofed or derived please help

maturity value/ please help.........

May. 15, 2010, Leven Corp. negotiated a short-term loan of $703,000. The loan is due Oct. 13, 2010, and carries a 7.04% interest rate. Use ordinary interest to calculate the interest. What is the... more

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.