10/03/13
When does 2nd car catch 1st car?
1st Car leaves point A at 5pm at avg speed of 80km/hr. Second car leaves point A 45 minutes later at 110km/hr. When does the 2nd car catch the 1st car. Show working.
10/03/13
Rewrite formulas and equations.
1. Solve for t in the equation -9 = t + 4s
2. Solve for A: B = 5/7(A - 11)
10/03/13
Solve the given linear system.
Solve the given linear system.
a. y = 5x - 3 y = 3x - 1
b. -2x + 3y = 8 3x + 5y = -12
c. 2x - 4y = -6 -x + 2y = 3
d. 5x + 10y = 70 5x + 25z = 270 10y + 25z =...
more
10/02/13
find the domain and range
suppose that f(x) = √(x2 -72) and g(x)= √(7-x)
for each function (h) below, find a formula for h (x) and the domain of h ( use internal notation)
a) h(x) = f composed with g of (x)
b) h(x) =...
more
10/01/13
at the grocery store a cucumber costs $0.33 and a green pepper costs $0.52. what combination of cucumbers and green peppers could you buy for exactly $5.00
this qustion is a problem solver
09/02/13
if there are two events, what probability expression best describes an exactly one suitation
using the union, intersection and complement expressions
02/26/13
Quadratic Equation Help
I'm solving a quadratic equation which is 2x^2-x-10=0 and I know that a=2 b=-1 and c=-10 ans with the problem put it into the formula which is -(-10 +- √ -1^2-4(2)(-10) and when I get my answer I...
more
02/19/13
Define when two events are mutually exclusive by an equation.
Define when two events are mutually exclusive by an equation.
11/01/12
how is the derivative of the inverse tan function = 1/sec2(tan^-1)
how do i get to that point how is it proofed or derived please help
10/20/12
maturity value/ please help.........
May. 15, 2010, Leven Corp. negotiated a short-term loan of $703,000. The loan is due Oct. 13, 2010, and carries a 7.04% interest rate. Use ordinary interest to calculate the interest.
What is the...
more
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.