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# Graph y=2tan(3x-30)+2 in degrees

came across this problem and it is suppose to be graphed in degrees. I have only graphed in radians. How do I do it?

### 2 Answers by Expert Tutors

Robert J. | Certified High School AP Calculus and Physics TeacherCertified High School AP Calculus and Ph...
4.6 4.6 (13 lesson ratings) (13)
1

y = 2tan[3(x-10)] + 2

By transformation,

Graph one period of y1 = tan x , where x is in degrees. This is an odd function with vertical asymptotes at x = -90 and x = 90 degrees.

Stretch it vertically by a factor of 2 to get y2 = 2tan x

Compress it horizontally by a factor of 3 to get y3 = 2tan 3x

Move it to the right by 10 degrees to get y4 = 2tan [3(x-10)]

Move it up by 2 unites to get y5 = 2tan[3(x-10)] + 2 <==Answer

George C. | Humboldt State and Georgetown graduateHumboldt State and Georgetown graduate
5.0 5.0 (2 lesson ratings) (2)
0

In radians the principal values for tangent go from -pi/2  to  pi/2.  In degrees this is from -90 to +90 degrees.  For this the argument of the tangent function must be in this domain.  Thus :

3x - 30 + 2  =  -90,   x=-62/3

3x - 30 + 2  =   90,   x=  118/3

-62/3  ≤  x  ≤  118/3

To plot, plug in the values in this domain.  The range will run from -2∞  ≤  y  ≤  2∞  very similar to a radians plot.