came across this problem and it is suppose to be graphed in degrees. I have only graphed in radians. How do I do it?

y = 2tan[3(x-10)] + 2

By transformation,

Graph one period of y1 = tan x , where x is in degrees. This is an odd function with vertical asymptotes at x = -90 and x = 90 degrees.

Stretch it vertically by a factor of 2 to get y2 = 2tan x

Compress it horizontally by a factor of 3 to get y3 = 2tan 3x

Move it to the right by 10 degrees to get y4 = 2tan [3(x-10)]

Move it up by 2 unites to get y5 = 2tan[3(x-10)] + 2 <==Answer