Consider the following circle: (x+1)^2 + (y-1)^2 =2

Question

What is the slope-intercept form of the line that is tangent to the circle and passes through the origin?

Answer 1

The tangent is perpendicular to the radius at the point of tangency.

The slope of the radius is -1, m = (1 - 0) / (-1 - 0 ).

The slope of the line perpendicular is the negative reciprocal, 1.

 

y = x        b = 0 since the line passes through the origin.