Print a file skipping first X lines in Bash?

Question

I have a very long file which I want to print but skipping the first 1e6 lines for example. I look into the cat man page but I did not see any option to do this. I am looking for a command to do this or a simple bash program.

Answer 1

Try:

tail -n +NUM FILE

Where NUM is the number of lines to skip

Please feel free to reach out for clarification