∫t/(1-t2) dt
Simple substitution works:
Let u = 1-t2
du = -2t dt, so du/(-2t) = dt
∫t/u du/(-2t) = -(1/2)∫1/u du = -(1/2)ln(u) + C = -(1/2)ln(1-t2) + C
Narmatha N.
asked 09/02/18
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