The percentage by volume of C3H8 in a mixture of C3H8,CH4 and CO is 36.5. Calculate the volume of CO2 produced when 100mL of mixture is burnt in excess of O2

Question

This question is from mole concept and stoicometry 

Please give me the full key.

 

Answer 1

At constant temperature and pressure:

Volume of C₃H₈ = 36.5 ml

Volume of CH₄ + CO = 100 ml - 36.5 ml = 63.5 ml

Combustion reactions:

C₃H₈ + 5O₂ ==> 3CO₂ + 4H₂O

CH₄ + 2O₂ ==> CO₂ + 2H₂O

CO + 1/2 O₂ ==> CO₂

On a mole basis, 1 mole C₃H₈ produces 3 moles CO₂ and 1 mole CH₄ and CO each form 1 mole CO₂

Or, looking at it another way, mls CO₂ = 3x36.5 + (100-36.5) = 109.5 + 63.5 = 173 mls of CO₂ formed