word problem

Question

If $1300 is invested at t% and $600 is invested at (t-3)%, what can be used to represent the interest drawn in one year?

Answer 1

Interest would be

$1300*t%+ $600(t-3)% =$(1300+600)*t%-$600*3% =

=$1900(t/100)-$600*0.03=$19*t-$6*3 =$19*t-$18 =$18(t-1)+t.