Can you help me solve this?

Question

1+sin/sin+cot-cos/cos=2/sin

Answer 1

(1+sin)/sin+(cot-cos)/cos=2/sin

(1+sin)/sin+([cos/sin]-cos)/cos=

(1/sin)+1+([cos/sin]-[sincos/sin]/cos=

(1/sin)+1+([cos-sincos]/sin)/cos=

(1/sin)+1+(cos-sincos)/sincos=

(1/sin)+1+(cos/sincos)-(sincos/sincos)=

(1/sin)+1+(1/sin)-1=

(1/sin)+(1/sin)=

2/sin