Bee, maybe I can help a little.
the decimal is 0.583333...
look at the repetend only, not the lag
the repetend is made up of the 3s and the lag is 58
the lag is what precedes the repetend
how many different digits repeat ? only one, the 3
let x=0.58333...
multiply both sides by 10 to the first power; why ? because one digit repeats, the 3
10x=5.83333...
- x=0.58333...
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9x=5.25000...
9x=5.25
x=5.25/9
x=525/900
simplify by dividing both terms by 25
x=21/36
simplify again by dividing by 3
x=7/12
here is another example...
0.6818181...
let x=0.681818181...
the lag is 6 and the repetend is 818181...
how many digits repeat ? two, the 8 and the 1
multiply both sides of the equation by 10 to the second power(100) because two digits repeat
100x=68.18181818...
- x=0.68181818...
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99x=67.50000000...
x=67.5/99
x=675/990
simplify by dividing by 5
x=135/198
simplify again by dividing by 9
x=15/22
look at your original problem 0.58333...
here is another way to solve the problem
multiply the decimal by the power of ten that puts the decimal point between the lag and the repetend
after that divide by the same power of ten
(100)(0.58333...)/(100)
58.333.../100
(58 1/3)/100 0.333...=3/9=1/3, 0.555...=5/9, and so on
also 0.727272...=72/99=8/11, 0.272727...=27/99=3/11 and so on
also 0.123123123...=123/999=41/333, 0.351351351...=351/999=117/333=39/111=13/37 and so on
getting back to the problem...
(58 1/3)/100=(175/3)/100=175/300=7/12
look at 0.6818181...
(10)(0.6818181...)/10
6.818181.../10
(6 81/99)/10
(6 9/11)/10=(75/11)/10=75/110=15/22
if you have any more questions let me know
Bee D.
08/26/14