J.R. S. answered 01/01/18
Tutor
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
2C + 3H2 ==>C2H6
Reactants
716.7 KJ/mole x 2 mole = 1433.4 kJ
433 KJ/mole x 3 moles = 1299 kJ
Products
1C-C = 348 kJ
6 C-H = 6 x 413 kJ = 2478
Total reactants = 1433 + 1299 = 2732 kJ
Total products = 348 + 2478 = 2826 kJ
2826 - 2732 = 94 kJ = ∆H