Separate variables to get dy = -6x3dx So, ∫dy = -∫6x3dx y = -(3/2)x4 + C Since y(0) = -4, we have -4 = 0 + C. So, C = -4 Therefore, y = -(3/2)x4 - 4

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Mark M. answered • 11/26/17

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Separate variables to get dy = -6x³dx

So, ∫dy = -∫6x³dx

y = -(3/2)x⁴ + C

Since y(0) = -4, we have -4 = 0 + C. So, C = -4

Therefore, y = -(3/2)x⁴ - 4

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Solve the Initial Value Problem.